WBBSE Class 7 Mathematics Solutions - নিজে করি 6.4

সমাধান :

(i) $(+2a) \times (+3b) \times (+5c) = (2 \times 3 \times 5) \times (a \times b \times c) = 30abc$

(ii) $(-2a) \times (+3b) \times (+5c) = (-2 \times 3 \times 5) \times (a \times b \times c) = -30abc$

(iii) $(+2a) \times (-3b) \times (+5c) = (2 \times -3 \times 5) \times (a \times b \times c) = -30abc$

(iv) $(+2a) \times (-3b) \times (-5c) = (2 \times -3 \times -5) \times (a \times b \times c) = 30abc$

(v) $(-2a) \times (-3b) \times (+5c) = (-2 \times -3 \times 5) \times (a \times b \times c) = 30abc$

(vi) $(-2a) \times (+3b) \times (-5c) = (-2 \times 3 \times -5) \times (a \times b \times c) = 30abc$

(vii) $(-2a) \times (-3b) \times (-5c) = (-2 \times -3 \times -5) \times (a \times b \times c) = -30abc$

(viii) $(-2p) \times (-2q) \times (-2r) = (-2 \times -2 \times -2) \times (p \times q \times r) = -8pqr$

(ix) $(+x) \times (+y) \times (-z) = (1 \times 1 \times -1) \times (x \times y \times z) = -xyz$

(x) $(-3p^2) \times (-4q^2) \times (-2r^2) = (-3 \times -4 \times -2) \times (p^2 \times q^2 \times r^2) = -24p^2q^2r^2$